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Free SSAT Math Practice Test — Grade 9

Math only, deliberately — the real SSAT (published by the Enrollment Management Association) also has verbal and reading sections, which we don't cover.

20 real practice questions at SSAT Upper Level difficulty, drawn from the same calibrated bank our adaptive practice uses. Work through them right here — every question has the answer and a step-by-step explanation one tap away.

Question 1 · Coordinate GraphsIntro
The graphs of y = 0.5x - 2 and y = 1.5x - 4 intersect at a single point. What is that point?
A(3, -0.5)
B(2, -1)
C(0, -2)
D(6, 1)
E(1.5, -1.25)
Show answer & explanation
Let's work it out
1.To find where the two lines meet, set their right-hand sides equal: 0.5x - 2 = 1.5x - 4.
2.Subtracting 0.5x from both sides gives -2 = x - 4, and adding 4 gives x = 2.
3.Substituting back into either equation yields y = 0.5(2) - 2 = -1, so the intersection point is (2, -1).
Answer: B) (2, -1)
Question 2 · PercentagesIntro
Regional Soccer Tournament Attendance
YearAttendance
0?
1?
212,100
The table shows the attendance at a regional soccer tournament for three years. The tournament director says attendance grew by exactly 10% each year from Year 0 to Year 2 through compound annual growth. If Year 2 attendance was 12,100 fans, what was the attendance at Year 0?
A11,000
B10,000
C14,641
D10,890
E9,680
Show answer & explanation
Let's work it out
1.Because attendance grew by 10% each year through compound growth, each year’s attendance equals the previous year’s attendance multiplied by 1.10.
2.To reverse two years of 10% compound growth, divide by 1.10 twice.
3.Dividing 12,100 by 1.10 gives 11,000 (Year 1 attendance), then dividing 11,000 by 1.10 gives 10,000.
4.The original Year 0 attendance was 10,000 fans.
Answer: B) 10,000
Question 3 · MathEasy
Model Cell Dimensions
Volume (cu cm)Side Length (cm)
11
82
273
18\frac{1}{8}?
A science class is modeling cells using cubes. The table below shows the volume of each model cell and the side length students need to compute. For the cell with a volume of 18\frac{1}{8} cubic centimeter, what is the side length in centimeters?
A2
B12\frac{1}{2}
C124\frac{1}{24}
D1512\frac{1}{512}
E38\frac{3}{8}
Show answer & explanation
Let's work it out
1.The side length of a cube equals the cube root of its volume.
2.To find the cube root of 18\frac{1}{8}, take the cube root of the numerator and the cube root of the denominator separately: the cube root of 1 is 1, and the cube root of 8 is 2, giving a side length of 12\frac{1}{2}.
3.This is confirmed by the pattern in the table, where the side length cubed always equals the volume.
Answer: B) 12\frac{1}{2}
Question 4 · GeometryEasy
Kite Frame Strut Lengths
StrutLength (cm)
Short strut 12.5
Short strut 26.0
Long outer strut6.5
A crafter is building a diamond-shaped kite frame. The table shows the planned lengths of three wooden struts. The two shorter struts meet at a right angle at the center of the kite. The crafter wants to add one straight diagonal brace connecting the outer ends of those two shorter struts. What length, in centimeters, should the diagonal brace be so that the triangle formed by the two shorter struts and the brace is a perfect right triangle?
A7.0
B8.5
C42.25
D6.5
E6.0
Show answer & explanation
Let's work it out
1.The two shorter struts (2.5 cm and 6.0 cm) meet at a right angle, making them the two legs of the right triangle.
2.The diagonal brace connecting their outer ends is the hypotenuse.
3.Applying the Pythagorean theorem: 2.5² + 6.0² = 6.25 + 36.00 = 42.25, and 42.25\sqrt{42.25} = 6.5 cm.
4.The correct answer is D.
Answer: D) 6.5
Question 5 · Coordinate GraphsEasy
Coordinate gridCoordinate grid, x-axis from -1 to 7, y-axis from -1 to 6. Points: (0, 2.0) at (0, 2), (4, 4.0) at (4, 4). Also shown: a line with slope 0.5 and y-intercept 2. x y -11234567-1123456(0, 2.0)(4, 4.0)
The graph shows the total monthly cost (in dollars) of a music streaming plan based on the number of premium song downloads purchased. Two points on the line are marked: (0, 2.0) and (4, 4.0). Which equation represents this linear relationship?
Ay = 0.5x + 2.0
By = 2.0x + 2.0
Cy = 1.5x + 1.5
Dy = 0.5x + 1.0
Ey = 2.0x + 0.5
Show answer & explanation
Let's work it out
1.Using the two marked points (0, 2.0) and (4, 4.0), the slope is (4.0 - 2.0) divided by (4 - 0), which equals 2.04\frac{0}{4} = 0.5.
2.The y-intercept is the value when x = 0, which is 2.0 directly from the first point.
3.Substituting into slope-intercept form gives y = 0.5x + 2.0, confirmed by plugging in x = 4: 0.5(4) + 2.0 = 4.0.
Answer: A) y = 0.5x + 2.0
Question 6 · IntegersEasy
Positions Along the Trail
LocationSigned Position in Miles
Tunnel-78\frac{7}{8}
Overlook?
Visitor Center0
The table gives signed positions along an east-west trail, measured in miles from the visitor center. A guide defines one ridge unit as the distance from Tunnel to Overlook, which is east of Tunnel. A shuttle route measuring 158\frac{15}{8} miles is exactly 3 ridge units long. What signed position should replace the question mark?
A58\frac{5}{8}
B194\frac{19}{4}
C-32\frac{3}{2}
D2940\frac{29}{40}
E-14\frac{1}{4}
Show answer & explanation
Let's work it out
1.If the Overlook position is x, one ridge unit is x - (-78\frac{7}{8}) = x + 78\frac{7}{8} miles.
2.Since 158x+78\displaystyle \frac{\frac{15}{8}}{x + \frac{7}{8}} = 3, the unit length is 58\frac{5}{8} mile, so x = 58\frac{5}{8} - 78\frac{7}{8} = -14\frac{1}{4}.
Answer: E) -14\frac{1}{4}
Question 7 · Arithmetic & Number SenseStandard
Cone Distances in the Six-Round Drill
RoundCone Distance in Meters
212.8
36.4
51.6
A basketball player completes a six-round conditioning drill. In each round, the player sprints from the starting line to a cone and then returns to the starting line. The cone distances form a geometric sequence, as shown in the table. How many meters farther does the player sprint during the first four rounds combined than during the final two rounds combined?
A92.8
B91.2
C45.6
D78.4
E100.8
Show answer & explanation
Let's work it out
1.The common ratio is 6.4 ÷ 12.8 = 0.5, so the six cone distances are 25.6, 12.8, 6.4, 3.2, 1.6, and 0.8 meters.
2.Doubling for each return trip gives 96 meters during the first four rounds and 4.8 meters during the final two rounds.
3.The player therefore sprints 96 - 4.8 = 91.2 meters farther during the first four rounds.
Answer: B) 91.2
Question 8 · GeometryStandard
A baker has a rectangular cooling rack with one side measuring 0.9 meters. When the baker stretches a measuring tape from one corner to the opposite corner, the diagonal measures 1.5 meters. The baker needs to know the length of the other side of the rack to check whether it will fit in the storage cabinet. What is the length, in meters, of the other side of the cooling rack?
A0.6
B1.44
C1.2
D1.0
E2.4
Show answer & explanation
Let's work it out
1.The two sides of a rectangle and its diagonal form a right triangle, with the diagonal as the hypotenuse.
2.Here the known leg is 0.9 m and the hypotenuse is 1.5 m, so the missing leg b satisfies 0.9² + b² = 1.5².
3.Computing: 0.81 + b² = 2.25, so b² = 1.44, and b = 1.44\sqrt{1.44} = 1.2 m.
4.This is the 3-4-5 Pythagorean triple scaled by 0.3 (0.9 = 3×0.3, 1.2 = 4×0.3, 1.5 = 5×0.3).
Answer: C) 1.2
Question 9 · PercentagesStandard
Changes in Snow Depth
StageSnow depth information
Before the storm16.00 centimeters
New snowfallIncrease of 37.5%
Snow settlesDecrease of 10%
Afternoon meltingDecrease of 20%
The table shows how the snow depth beside a school weather station changes during a storm and the following afternoon. After all the stages shown, another snowfall begins. How many centimeters of new snow must accumulate to bring the depth to exactly 18.00 centimeters?
A17.56
B6.21
C1.80
D2.16
E0.80
Show answer & explanation
Let's work it out
1.The new snowfall changes the depth to 16.00 × 1.375 = 22.00 centimeters.
2.Successive decreases then give 22.00 × 0.90 × 0.80 = 15.84 centimeters.
3.Therefore, 18.00 − 15.84 = 2.16 centimeters of additional snow must accumulate.
Answer: D) 2.16
Question 10 · ProbabilityStandard
A swim meet replay station can create a clip by choosing one of 5 race recordings, one camera angle, one of 4 playback speeds, and one starting point. The playback speeds are 0.5, 0.75, 1.0, and 1.25 times normal speed. Starting points occur every 0.8 second from 0.0 through 2.4 seconds, inclusive. If the station offers about 610 distinct clips, which is closest to the number of camera angles available?
A6
B38
C8
D10
E25
Show answer & explanation
Let's work it out
1.There are 4 starting points: 0.0, 0.8, 1.6, and 2.4 seconds.
2.Each camera angle therefore produces 5 × 4 × 4 = 80 possible clips.
3.Since 610 ÷ 80 = 7.625, the number of camera angles is closest to 8.
Answer: C) 8
Question 11 · Ratios & ProportionsStandard
For a set of handmade bracelets, Nia has one bead mix that is 13\frac{1}{3} metallic beads and another that is 34\frac{3}{4} metallic beads. She begins with 1 18\frac{1}{8} cups of the first mix but uses 38\frac{3}{8} cup on a different project. She combines all of the remaining first mix with some of the second mix so that exactly 12\frac{1}{2} of the finished blend is metallic beads. How many cups of the second mix does she use?
A98\frac{9}{8}
B16\frac{1}{6}
C34\frac{3}{4}
D23\frac{2}{3}
E12\frac{1}{2}
Show answer & explanation
Let's work it out
1.After the other project, 34\frac{3}{4} cup of the first mix remains, containing 14\frac{1}{4} cup of metallic beads.
2.If x is the amount of the second mix, equating the metallic portion to half of the finished blend gives 14\frac{1}{4} + 3x/4 = 12\frac{1}{2} times the quantity 34\frac{3}{4} + x.
3.Solving this equation gives x = 12\frac{1}{2} cup.
Answer: E) 12\frac{1}{2}
Question 12 · Data & StatisticsStandard
Set P contains half as many numbers as Set Q, and the mean of Set P is 34\frac{3}{4}. One-fourth of the numbers in Set Q, with a mean of 12\frac{1}{2}, are removed. The mean of the numbers in Set P together with the numbers remaining in Set Q is 710\frac{7}{10}. What was the original mean of Set Q?
A710\frac{7}{10}
B58\frac{5}{8}
C12\frac{1}{2}
D23\frac{2}{3}
E712\frac{7}{12}
Show answer & explanation
Let's work it out
1.Let Set Q contain 8 numbers, so Set P contains 4 and 2 are removed from Set Q.
2.The combined sum after removal is 10 times 710\frac{7}{10}, or 7; subtracting the sum of Set P leaves 4 for the remaining part of Set Q.
3.Restoring the removed sum gives an original Set Q total of 5, so its mean is 58\frac{5}{8}.
Answer: B) 58\frac{5}{8}
Question 13 · Arithmetic & Number SenseStandard
Classroom Reading Challenge
WeekWords Read
214000
526000
During a classroom reading challenge, the number of words read by the class each week forms an arithmetic sequence. According to the table, how many words does the class read altogether during the first 8 weeks?
A352000
B38000
C208000
D192000
E160000
Show answer & explanation
Let's work it out
1.From week 2 to week 5, the total increases by 12000 words over 3 equal steps, so the weekly increase is 4000 words.
2.Thus, the first and eighth weekly totals are 10000 and 38000, respectively.
3.Their average is 24000, so the total for 8 weeks is 8 × 24000 = 192000.
Answer: D) 192000
Question 14 · Data & StatisticsStandard
Data Sets
PositionSet PSet Q
17.83.9
24.68.4
39.36.2
45.75.1
How much greater is the sum of the two largest entries in Set P than the sum of the two smallest entries in Set Q?
A1.3
B26.1
C0.3
D13.2
E8.1
Show answer & explanation
Let's work it out
1.The two largest entries in Set P sum to 9.3 + 7.8 = 17.1.
2.The two smallest entries in Set Q sum to 3.9 + 5.1 = 9.0.
3.The difference is 17.1 − 9.0 = 8.1.
Answer: E) 8.1
Question 15 · Equations & InequalitiesHard
If (34\frac{3}{4})[x - 2yz3\frac{2y - z}{3}] - x+z5\frac{x + z}{5} = (23\frac{2}{3})(y - x2\frac{x}{2}), which relation must also hold?
Ax = 70y27z53\frac{70y - 27z}{53}
Bx = 70y3z63\frac{70y - 3z}{63}
Cx = 70y3z53\frac{70y - 3z}{53}
Dx = 70y3z13\frac{70y - 3z}{13}
Ex = 70y+27z53\frac{70y + 27z}{53}
Show answer & explanation
Let's work it out
1.Multiply the relation by 60 and distribute to obtain 45x - 30y + 15z - 12x - 12z = 40y - 20x.
2.Combining like terms and collecting the x-terms gives 53x = 70y - 3z.
3.Therefore, x = 70y3z53\frac{70y - 3z}{53}.
Answer: C) x = 70y3z53\frac{70y - 3z}{53}
Question 16 · Algebraic ExpressionsHard
If a is a negative integer and x2 + ax - 72 has x-a as a factor, what is the constant term of the other binomial factor?
A12
B-6
C-12
D-3
E-72
Show answer & explanation
Let's work it out
1.Write the other factor as x+k and compare (x-a)(x+k) with x2+ax-72.
2.The coefficient relationships give k=2a and -ak=-72, so a2=36.
3.Since a is negative, a=-6 and the other constant is k=-12.
Answer: C) -12
Question 17 · MathHard
In a music app, the sound-processing rule q is applied before the rule p, where p(x) = √20xx12\frac{20 - x}{x - 12} and q(n) = 129n2\displaystyle \frac{12}{\sqrt{9 - n} - 2}. Which whole-number setting n can be entered into q but produces a value that cannot then be entered into p?
A1
B9
C8
D0
E5
Show answer & explanation
Let's work it out
1.The rule q accepts 0 because its radicand is nonnegative and its denominator is not zero.
2.Substitution gives q(0) = 12.
Answer: D) 0
Why the other choices are tempting: The value 12 cannot be entered into p because it makes the denominator of p equal zero, so the required setting is 0.
Question 18 · Equations & InequalitiesHard
If -32ab4\frac{2a - b}{4} + 5a+2b6\frac{a + 2b}{6} = c - d, which expression is equal to b?
A14a+12c12d32\frac{14a + 12c - 12d}{32}
B8a+12c12d29\frac{-8a + 12c - 12d}{29}
C8a+12c12d29\frac{8a + 12c - 12d}{29}
D8a+12c12d11\frac{8a + 12c - 12d}{11}
E8a+12cd29\frac{8a + 12c - d}{29}
Show answer & explanation
Let's work it out
1.Multiply the equation by 12 to obtain -9(2a - b) + 10(a + 2b) = 12c - 12d.
2.Distributing and combining like terms gives -8a + 29b = 12c - 12d.
3.Isolating b yields b = 8a+12c12d29\frac{8a + 12c - 12d}{29}.
Answer: C) 8a+12c12d29\frac{8a + 12c - 12d}{29}
Question 19 · Algebraic ExpressionsHard
If p and q are nonzero real numbers and (p-3q2)/(pq-2) = 1681\frac{16}{81}, what is the value of (p-6q6)/(pq)0?
A827\frac{8}{27}
B72964\frac{729}{64}
C2566561\frac{256}{6561}
D64729\frac{64}{729}
E1681\frac{16}{81}
Show answer & explanation
Let's work it out
1.The given expression is (qp\frac{q}{p})4, so the magnitude of qp\frac{q}{p} is 23\frac{2}{3}.
2.The target expression is (qp\frac{q}{p})6 because (pq)0 equals 1.
3.Since the sixth power is even, either possible sign of qp\frac{q}{p} gives 64729\frac{64}{729}.
Answer: D) 64729\frac{64}{729}
Question 20 · MathHard
Values of P, Q, and R
xP(x)Q(x)R(x)
018\frac{1}{8}18\frac{1}{8}18\frac{1}{8}
138\frac{3}{8}28\frac{2}{8}48\frac{4}{8}
258\frac{5}{8}48\frac{4}{8}98\frac{9}{8}
378\frac{7}{8}88\frac{8}{8}168\frac{16}{8}
498\frac{9}{8}168\frac{16}{8}258\frac{25}{8}
The table gives values of three functions. If each displayed pattern continues, which lists the functions in order from slowest eventual growth to fastest eventual growth?
AQ, P, R
BQ, R, P
CR, P, Q
DP, Q, R
EP, R, Q
Show answer & explanation
Let's work it out
1.To determine eventual growth rates, identify what type of function each one is.
2.For P: compute consecutive differences of the outputs.
3.If the table shows outputs increasing by a constant amount each step, P has a constant first difference — making it a **linear** function.
4.For R: check whether the outputs follow a pattern where the numerators are perfect squares (1, 4, 9, 16, …).
5.If so, R grows as a **quadratic** function.
6.For Q: check whether consecutive outputs have a constant ratio (each output is a fixed multiple of the previous one).
7.A constant multiplicative factor means Q is an **exponential** function.
8.Once the function types are identified, apply the fundamental growth-rate hierarchy: linear functions are eventually outpaced by quadratic functions, which are eventually outpaced by exponential functions — regardless of how the values compare in the early rows of the table.
9.Therefore, from slowest to fastest eventual growth: **P (linear), R (quadratic), Q (exponential)**, which corresponds to answer choice **E**.
Answer: E) P, R, Q

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